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Amb
Amb the Hitched.

Posted: Wed Jun 06, 2012 8:50 am    Post subject: 1

I have a grid, 5 x 5.

Into it I place the following: (. = Empty Cell)

 Code: ..... .NIN. .IEI. .NIN. .....

The word NINE can be spelt out eight ways. Starting with any N, and moving to a connected I, then to another connected N, then finally the E.

If I add an E like this:
 Code: ..... .NINE .IEI. .NIN. .....

or this:
 Code: ....E .NIN. .IEI. .NIN. .....

I increase the number of nine's to TEN.

If I add an I, or another N in varying places, I get other counts of NINE.

I want there to be exactly 9 nines.

How might I achieve this, by filling out one more cell only.

Edit: My original solution to this was to just shove a 9 somewhere in the cells. I was going to exclude that, but forgot.
There is a better solution. So you cannot use the numbers 0 through 9.

Last edited by Amb on Wed Jun 06, 2012 8:24 pm; edited 2 times in total
Zag
Tired of his old title

Posted: Wed Jun 06, 2012 9:00 am    Post subject: 2

 Code: ..... .NINN .IEI. .NIN. .....
Amb
Amb the Hitched.

Posted: Wed Jun 06, 2012 9:08 am    Post subject: 3

That creates 10 "NINE"'s. The two extra being:

 Code: ..... ...NN ..EI. ..... .....

and

 Code: ..... ....N ..EI. ...N. .....

Last edited by Amb on Wed Jun 06, 2012 9:18 am; edited 2 times in total
LordKinbote
Daedalian Member

 Posted: Wed Jun 06, 2012 9:17 am    Post subject: 4 Place the character "9" in any empty cell.
Amb
Amb the Hitched.

 Posted: Wed Jun 06, 2012 9:18 am    Post subject: 5 That does work, so let's extend the rules slightly. No numbers (And it was actually a solution I considered, and then forgot about)Last edited by Amb on Wed Jun 06, 2012 9:20 am; edited 1 time in total
LordKinbote
Daedalian Member

 Posted: Wed Jun 06, 2012 9:20 am    Post subject: 6 Fine, ya party pooper. Place an E in any corner.
Amb
Amb the Hitched.

Posted: Wed Jun 06, 2012 9:21 am    Post subject: 7

Like in my examples at the top. That creates too many.

 Code: ....E .NIN. .IEI. .NIN. .....

An E in any corner creates two extra:

 Code: ....E .NIN. ..... ..... .....

and

 Code: ....E ...N. ...I. ...N. .....

Last edited by Amb on Wed Jun 06, 2012 9:22 am; edited 1 time in total
The Great Crep'er
2% Spambot

 Posted: Wed Jun 06, 2012 9:22 am    Post subject: 8 Stupid Question time: We can only do this by filling out another I or N, or is E also an available option?
LordKinbote
Daedalian Member

Posted: Wed Jun 06, 2012 9:23 am    Post subject: 9

 Amb wrote: Like in my examples at the top. That creates too many.

Oh, oops.
The Great Crep'er
2% Spambot

 Posted: Wed Jun 06, 2012 9:26 am    Post subject: 10 Ah, okay. This seems like it could be solvable by just simply going through all the possible cells with N's and I's respectively, but I suspect there is a bit more to it.
LordKinbote
Daedalian Member

Posted: Wed Jun 06, 2012 9:27 am    Post subject: 11

 Code: ..... .NIN. .IEI. .NIN. ...X.

It's kind of a fat 9, but it's a 9.
The Great Crep'er
2% Spambot

Posted: Wed Jun 06, 2012 9:38 am    Post subject: 12

TGC wrote:

 Code: ..... .NIN. .NEI. .NIN. .....

This will, I'm afraid, be invalid, but I'm giving it the old college try.
Amb
Amb the Hitched.

Posted: Wed Jun 06, 2012 9:40 am    Post subject: 13

Good try, but I think that makes a lot more than 9.

Remember that

 Code: ..... ..... .NE.. .NI.. .....

is itself 2 combinations.

And to make it clear, you cannot overwrite an existing cell.
LordKinbote
Daedalian Member

 Posted: Wed Jun 06, 2012 9:43 am    Post subject: 14 Oh, ha. That's funny. I guess the IX is the last nine.
Amb
Amb the Hitched.

 Posted: Wed Jun 06, 2012 9:45 am    Post subject: 15 Yeah thats the one IX is the right answer. Add an X into the grid to make Roman Numeral IX The question is, could it become a chestnut?
The Great Crep'er
2% Spambot

 Posted: Wed Jun 06, 2012 9:50 am    Post subject: 16 Ha! That's clever! Or as you say in Latin (speaking from a horribly uneducated side) 'scitus'!
Amb
Amb the Hitched.

Posted: Wed Jun 06, 2012 8:23 pm    Post subject: 17

So the question now for you all: Can you construct the word ELEVEN in a similar grid, so that it appears exactly ELEVEN times.

For example:
 Code: EELEE LVNVL EELEE

ELEVEN appears many times in here, but I stopped counting once I hit twelve.

In this case, you cannot write anything other than E,L,V or N.

The grid remains 5x5, until such time we conclude that it isn't possible to do in a 5x5. Bonus points for anyone achieving in a 4x5 or 4x4 - but I'm not even going to try that small.
Amb
Amb the Hitched.

 Posted: Wed Jun 06, 2012 8:25 pm    Post subject: 18 Better yet, can we construct an ELEVEN puzzle, such that adding 1 more character creates the 11th.
Trojan Horse
Daedalian Member

Posted: Thu Jun 07, 2012 3:16 am    Post subject: 19

 Code: ELEVE EL.VN ...V. ELEVE ...VN
Trojan Horse
Daedalian Member

Posted: Thu Jun 07, 2012 3:33 am    Post subject: 20

 Code: VELE EVL. NNV. .EVE ELVN

Beat THAT.
Amb
Amb the Hitched.

 Posted: Thu Jun 07, 2012 9:09 pm    Post subject: 21 I haven't checked that combination, but it has the ability to have one more ELEVEN added by adding I and I into the two consecutive gaps. And that could easily be evolved into a puzzle the same as the NINE one. I was also thinking about doing one where you add X to the Nine puzzle, and then around it, put two 3's to make 3X3.
Trojan Horse
Daedalian Member

Posted: Fri Jun 08, 2012 4:31 am    Post subject: 22

Oh man. It CAN be beaten. Here are 11 ELEVENs in a 5x3 space:

 Code: ELE VEV ENE E.E LEV

Anyone up for a 4x3?
Thok
Oh, foe, the cursed teeth!

Posted: Fri Jun 08, 2012 9:39 am    Post subject: 23

Changing up Troj's slightly to involve less added letters for the 11th eleven

 Code: ELE.. VEV.. ENELE
Trojan Horse
Daedalian Member

Posted: Fri Jun 08, 2012 9:49 pm    Post subject: 24

Changing up Thok's slightly to involve the same number of letters, but cram them into a 4x3 space:

 Code: ELE VEV ENE .EL

Also note that, by coincidence, Thok got us down to exactly 11 letters.
Amb
Amb the Hitched.

 Posted: Mon Jun 11, 2012 5:16 am    Post subject: 25 I find the counting really annoying. But I was contemplating trying to mix 11 ELEVEN and 12 TWELVES in as small a space as I could...
DejMar
(Possibly a robot)

Posted: Tue Aug 21, 2012 5:35 am    Post subject: 26

 Amb wrote: The word NINE can be spelt out eight ways. Starting with any N, and moving to a connected I, then to another connected N, then finally the E.

[It is assumed that each distinct letter (character) is used no more than once.]
 LordKinbote wrote: Place the character "9" in any empty cell.

 Amb wrote: That does work, so let's extend the rules slightly. No numbers (And it was actually a solution I considered, and then forgot about)

With the new rule of no adding of numbers, adding a Roman numeral would be disallowed. As a translingual symbol, the I itself can represent 9 as it is the ninth letter in the modern Latin and English alphabets. Thus, allowing such, the grid would already begin with twelve 'nines'. Therefore, adding an X to give IX could not be a valid solution.

I did consider, limited to only letters, that a single letter added might give the word "nine" in another language, such as adding an 'S' for SIE in Balinese or Benuaq. Yet, NEIN, is "nine" in German which would begin the grid with no less than 20 "nines". Thus, that possibility is also ruled out as a solution.

I would say, given the wording of the puzzle, there is no solution.
LordKinbote
Daedalian Member

Posted: Tue Aug 21, 2012 10:34 pm    Post subject: 27

DejMar wrote:
 Amb wrote: The word NINE can be spelt out eight ways. Starting with any N, and moving to a connected I, then to another connected N, then finally the E.

[It is assumed that each distinct letter (character) is used no more than once.]
 LordKinbote wrote: Place the character "9" in any empty cell.

 Amb wrote: That does work, so let's extend the rules slightly. No numbers (And it was actually a solution I considered, and then forgot about)

With the new rule of no adding of numbers, adding a Roman numeral would be disallowed. As a translingual symbol, the I itself can represent 9 as it is the ninth letter in the modern Latin and English alphabets. Thus, allowing such, the grid would already begin with twelve 'nines'. Therefore, adding an X to give IX could not be a valid solution.

I did consider, limited to only letters, that a single letter added might give the word "nine" in another language, such as adding an 'S' for SIE in Balinese or Benuaq. Yet, NEIN, is "nine" in German which would begin the grid with no less than 20 "nines". Thus, that possibility is also ruled out as a solution.

I would say, given the wording of the puzzle, there is no solution.

NEIN is "no". NEUN is "nine".
DejMar
(Possibly a robot)

 Posted: Wed Aug 22, 2012 5:20 am    Post subject: 28 I should have said Pennsylvanian and Palatine German. In German proper, neun is correct. In the two aforementioned dialects, nein is correct.
novice
No harm. Pun intended!

 Posted: Wed Aug 22, 2012 7:54 am    Post subject: 29 Also, nine in Norwegian is NI.
mathgrant
A very tilted cell member

Posted: Fri Sep 14, 2012 4:50 am    Post subject: 30

 Code: ONE TW OO REE EHT FOU FRR FIVE FFIF SSX SIX SEV .EE NNN EIGT EIGH NN. EIN N.. TENT TENE

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My logic puzzle blog
Amb
Amb the Hitched.

 Posted: Sat Sep 15, 2012 8:27 pm    Post subject: 31 mathgrant, that is quite cool. Obviously I have only just seen your post now. Thanks for posting that.
DejMar
(Possibly a robot)

Posted: Sun Sep 16, 2012 1:26 am    Post subject: 32

 Amb wrote: mathgrant, that is quite cool.

I think so, too. The only improvement I can see is to reduce one of the letters for FIVE:

 Code: VIFI FEV

And, with ELEVEN already solved, comes TWELVE:
 Code: WTWE WEVL  ELE
Amb
Amb the Hitched.

Posted: Fri Nov 09, 2012 2:28 am    Post subject: 33

Is there a technique to counting these things?

eg:
 Code: HTHIR ITHIRT REENEE

This is a random mix of thirteens that probably doesn't add right. But counting them is doing my head in. It looks like there should be a nice easy way of just counting the branching spots or something... Anyone got any ideas.
mathgrant
A very tilted cell member

Posted: Fri Nov 09, 2012 2:49 am    Post subject: 34

Amb wrote:
Is there a technique to counting these things?

eg:
 Code: HTHIR ITHIRT REENEE

This is a random mix of thirteens that probably doesn't add right. But counting them is doing my head in. It looks like there should be a nice easy way of just counting the branching spots or something... Anyone got any ideas.

The EE's on the left are part of a single THIRTEEN, and the EE's on the right are part of 2x2x2x2=16 of them. This one's easy.
_________________
My logic puzzle blog
DejMar
(Possibly a robot)

Posted: Wed Nov 14, 2012 7:01 am    Post subject: 35

 Code: THIRE RHIET ITEN_
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